0=-40x^2+44x-8.1

Solution for 0=-40x^2+44x-8.1 equation:

0=-40x^2+44x-8.1

We move all terms to the left:

0-(-40x^2+44x-8.1)=0

We add all the numbers together, and all the variables

-(-40x^2+44x-8.1)=0

We get rid of parentheses

40x^2-44x+8.1=0

a = 40; b = -44; c = +8.1;
Δ = b2-4ac
Δ = -442-4·40·8.1
Δ = 640
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{640}=\sqrt{64*10}=\sqrt{64}*\sqrt{10}=8\sqrt{10}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-44)-8\sqrt{10}}{2*40}=\frac{44-8\sqrt{10}}{80}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-44)+8\sqrt{10}}{2*40}=\frac{44+8\sqrt{10}}{80}
$